# std::vector<T,Allocator>::pop_back

From cppreference.com
< cpp‎ | container‎ | vector

void pop_back(); |  | (constexpr since C++20)

Removes the last element of the container.

Calling `pop_back` on an empty container results in undefined behavior.

Iterators and references to the last element are invalidated. The `end()` iterator is also invalidated.

### Parameters

(none)

### Return value

(none)

### Complexity

Constant.

### Exceptions

Throws nothing.

### Example

Run this code

    #include <vector>
    #include <iostream>

    namespace stq {
    template<typename T>
    void println(auto, const T& xz)
    {
        std::cout << '[';
        bool first{true};
        for (auto const& x : xz)
            std::cout << (first ? first = false, "" : ", ") << x;
        std::cout << "]\n";
    }
    }

    int main()
    {
        std::vector<int> numbers{1, 2, 3};
        stq::println("{}", numbers);
        while (not numbers.empty())
        {
            numbers.pop_back();
            stq::println("{}", numbers);
        }
    }

Output:

    [1, 2, 3]
    [1, 2]
    [1]
    []

### See also

push_back | adds an element to the end (public member function)

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