# std::function_ref::operator=

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< cpp‎ | utility‎ | functional‎ | function ref

constexpr function_ref& operator=( const function_ref& ) noexcept = default; | (1) | (since C++26)
template< class T > constexpr function_ref& operator=( T ) = delete; | (2) | (since C++26)

1) Copy assignment operator is explicitly-defaulted. `std::function_ref` satisfies `copyable` and TriviallyCopyable. This defaulted assignment operator performs a shallow copy of the stored `thunk-ptr` and `bound-entity`.
2) User-defined assignment operator is explicitly-deleted if T is not the same type as `std::function_ref`, std::is_pointer_v<T> is false, and T is not a specialization of std::nontype_t. This overload participates in overload resolution only if the constraints are satisfied in the conditions above.

### Return value

*this

### See also

(constructor) | constructs a new `function_ref` object (public member function)
operator= | replaces or destroys the target (public member function of `std::copyable_function`)
operator= | assigns a new target (public member function of `std::function<R(Args...)>`)
operator= | replaces or destroys the target (public member function of `std::move_only_function`)

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